We know that the fusing of the fuse is caused by the melting of the fuse by the heat released by the overcurrent, and the energy that can blow the fuse is the melting heat value I2t of the fuse. In theory, as long as the energy required for the fuse to melt is greater than The energy released by the instantaneous pulse current will not break the fuse, that is, the fuse can resist the impact of this pulse. Generally, slow-blow fuses have this characteristic.
So has there been any change in the fuse that has resisted an instantaneous pulse? It depends on how much it is hurt by the pulse. If the pulse energy is much smaller than the melting heat energy of the fuse, and the impact on the fuse is small, then the fuse can accept many times of impact without being broken, and vice versa. If the pulse energy is close to the melting heat of the fuse, the fuse will suffer a lot of damage once it is impacted, then it may not be able to withstand the second impact, that is to say: the fuse will be damaged after each pulse impact. A certain degree of damage, that is, its ability to withstand pulses is weakened or I2t is reduced, and the degree of weakening or reduction is proportional to the energy of the pulse.
If we want the fuse to withstand the impact of multiple instantaneous pulses, we must put enough margin between the I2t of the fuse and the pulse energy. Different electrical products have different pulses due to their different service life and switching frequency. , so the supplier of the fuse should provide the corresponding reference data, that is, corresponding to different pulse times, it is necessary to choose different multiples of the I2t of the fuse to the pulse energy.
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